83. Limiting Reactants (Section) When benzene (C6H6) reacts with bromine (Br2), bromobenzene (C6H5Br) is obtained: (a) When 30.0 g of benzene reacts with 65.0 g of bromine, what is the theoretical yield of bromobenzene?; (b) If the actual yield of bromobenzene is 42.3 g, what is the percentage yield?
Answer : For the reaction given above is that the benzene reacts with bromine to give bromobenzene.we have to calculate the molar mass of the following compound . C6H6+Br2C6H5Br+HBr. To calculate the molar mass of the following compound. We have to know the atomic number and atomic weight of the elements present in the compound . C6H6=[6(12.0g)+6(1.01g)]/mol . =(72.0g+6.06g)/mol . =78.06g/mol. Br2=2*79.9g/mol. =159.8g/mol. Now by combining the molar mass of both the compounds we get the molar mass of bromobenzene. Step 2 of 4 To determine the limiting agent : First we have to define the limiting agent The limiting reagent (or limiting reactant) in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent, since the reaction cannot continue without it.