Step-by-step help: Determining Convergence or Divergence In Exercises 526, determine the
Chapter 9, Problem 26(choose chapter or problem)
Determining Convergence or Divergence In Exercises 5-26,determine the convergence or divergence of the series.
\(\sum_{n=1}^{\infty} \frac{2(-1)^{n+1}}{e^{n}+e^{-n}}=\sum_{n=1}^{\infty}(-1)^{n+1} \operatorname{sech} n\)
Text Transcription:
Sum_n=1^infinity 2(-1)^n+1/e^n+e^-n=Sum_n=1^infinity (-1)^n+1 sech n
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