Solved: Writing an Equivalent Series In Exercises 73 and 74, write an equivalent series
Chapter 9, Problem 74(choose chapter or problem)
Writing an Equivalent Series In Exercises 73 and 74, write an equivalent series with the index of summation beginning at n = 0.
\(\sum_{n=2}^{\infty} \frac{9^{n}}{(n-2) !}\)
Text Transcription:
Sum_n=2^infinity 9^n/(n-2)!
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