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Get Full Access to Calculus: Early Transcendental Functions - 6 Edition - Chapter 9.9 - Problem 2
Get Full Access to Calculus: Early Transcendental Functions - 6 Edition - Chapter 9.9 - Problem 2

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# ?In Exercises 1-4, find a geometric power series for the function, centered at 0, (a) by the technique shown in Examples 1 and 2, and (b) by long divis

ISBN: 9781285774770 141

## Solution for problem 2 Chapter 9.9

Calculus: Early Transcendental Functions | 6th Edition

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Problem 2

In Exercises 1-4, find a geometric power series for the function, centered at 0, (a) by the technique shown in Examples 1 and 2, and (b) by long division.

$$f(x)=\frac{1}{2+x}$$

Text Transcription:

f(x) = 1 / 2 + x

Step-by-Step Solution:

Step 1 of 5) Figure 3.36 The derivative of ƒ-1(x) = 1x at the point (4, 2) is the reciprocal of the derivative of ƒ(x) = x2 at (2, 4) (Example 1).

Step 2 of 2

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