Solution: Using a Power Series In Exercises 1726, use the power series to determine a
Chapter 9, Problem 20(choose chapter or problem)
Using a Power Series In Exercises 17-26, use the power series
\(\frac{1}{1+x}=\sum_{n=0}^{\infty}(-1)^{n} x^{n}\)
to determine a power series, centered at 0, for the function. Identify the interval of convergence.
\(f(x)=\frac{2}{(x+1)^{3}}=\frac{d^{2}}{d x^{2}}\left[\frac{1}{x+1}\right]\)
Text Transcription:
1 / 1 + x = sum_{n = 0}^{infty}(-1)^{n} x^n
f(x) = 2 / (x +1)^3 = d^2 / dx^2 [1 / x + 1]
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer