Ramanujan and Pi Use a graphing utility to show that
Chapter 9, Problem 61(choose chapter or problem)
Use a graphing utility to show that
\(\frac{\sqrt{8}}{9801} \sum_{n=0}^{\infty} \frac{(4 n) !(1103+26,390 n)}{(n !) 396^{4 n}}=\frac{1}{\pi}\).
Text Transcription:
sqrt{8} / 9801 sum_{n = 0}^{infty} (4 n)!(1103 + 26,390 n) / (n!) 396^4n = 1 / pi
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