In Exercises 1–6, match the equation with its graph. [The graphs are labeled (a), (b), (c), (d), (e), and (f).]
(x-2)^\2 / 16 + (y + 1)^2 / 4 = 1
Step 1 of 5) Proof Part (1). If ƒ(c) 6 0, then ƒ(x) 6 0 on some open interval I containing the point c, since ƒ is continuous. Therefore, ƒ is decreasing on I. Since ƒ(c) = 0, the sign of ƒ changes from positive to negative at c so ƒ has a local maximum at c by the First Derivative Test.