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Textbooks / Calculus / Calculus: Early Transcendental Functions 6 / Chapter 10.1 / Problem 7

?In Exercises 7-14, find the vertex, focus, and directrix of the parabola, and sketch its graph. \(y^{2}=-8 x\)

Calculus: Early Transcendental Functions | 6th Edition | ISBN: 9781285774770 | Authors: Ron Larson ISBN: 9781285774770 141

Solution for problem 7 Chapter 10.1

Calculus: Early Transcendental Functions | 6th Edition

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Calculus: Early Transcendental Functions | 6th Edition | ISBN: 9781285774770 | Authors: Ron Larson

Calculus: Early Transcendental Functions | 6th Edition

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Problem 7

In Exercises 7-14, find the vertex, focus, and directrix of the parabola, and sketch its graph.

\(y^{2}=-8 x\)

Text Transcription:

y^{2} = -8x

Step-by-Step Solution:

Step 1 of 5) After the integral sign in the notation we just defined, the integrand function is always followed by a differential to indicate the variable of integration. We will have more to say about why this is important in Chapter 5. Using this notation, we restate the solutions of Example 1, as follows:

Step 2 of 2

Chapter 10.1, Problem 7 is Solved
Textbook: Calculus: Early Transcendental Functions
Edition: 6
Author: Ron Larson
ISBN: 9781285774770

This full solution covers the following key subjects: . This expansive textbook survival guide covers 134 chapters, and 10738 solutions. Calculus: Early Transcendental Functions was written by and is associated to the ISBN: 9781285774770. Since the solution to 7 from 10.1 chapter was answered, more than 227 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Calculus: Early Transcendental Functions, edition: 6. The answer to “?In Exercises 7-14, find the vertex, focus, and directrix of the parabola, and sketch its graph.\(y^{2}=-8 x\)Text Transcription:y^{2} = -8x” is broken down into a number of easy to follow steps, and 20 words. The full step-by-step solution to problem: 7 from chapter: 10.1 was answered by , our top Calculus solution expert on 11/14/17, 10:53PM.

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