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Get Full Access to Chemistry: A Molecular Approach - 3 Edition - Chapter 4 - Problem 56e
Get Full Access to Chemistry: A Molecular Approach - 3 Edition - Chapter 4 - Problem 56e

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# What is the molarity of Cl- in each solution?a. 0.200 M

ISBN: 9780321809247 1

## Solution for problem 56E Chapter 4

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition

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Problem 56E

What is the molarity of Cl- in each solution?

a. 0.200 M NaCl         b. 0.150 M SrCl2

c. 0.100 M AlCl3

Step-by-Step Solution:
Step 1 of 3

Solution 56E: Solution: Here, we are going to write the balanced chemical equations for the given set of reactions with the help of reactivity series. Step1: The reactivity series is a list of metals arranged in the order of their decreasing activities. We can say that all metals are not equally reactive. That is why, reactive metals can displace less reactive metals from their compounds in solution or molten form. In order to know, which metal is more reactive, several experiments were performed, and finally a series known as the reactivity or activity series was developed. Step2: a) Nickel metal is added to a solution of copper(ll) nitrate Since Nickel is placed above copper in the reactivity series, it is more reactive than copper. Hence, it will displace copper from its nitrate solution. The balanced chemical equation is: Ni(s) + Cu(NO ) 3 2-------> Ni(NO ) (aq3 2u(s) b) A solution of zinc nitrate is added to a solution of magnesium sulfate Since, none of the reactant metals are in elemental form so no reaction takes place between the two salts. Instead, a double displacement reaction may occur. Hence, the balanced chemical equation is: Zn(NO )3 2 + MgSO (aq) 4-----> ZnSO (aq) + M4NO ) (aq) 3 2 c) Hydrochloric acid is added to gold metal Since, hydrogen is placed above gold in the activity series, it is more reactive than gold. Hence, no reaction occurs when hydrochloric acid is added to gold metal. HCl(aq) + Au(s) --------> NR d) Chromium metal is immersed in an aqueous solution of cobalt(ll) chloride Since chromium is placed above cobalt in the reactivity series, it is more reactive than cobalt. Hence, it will displace cobalt from its chloride solution. The balanced chemical equation is: 2Cr(s) + 3CoCl (aq2-------> 2CrCl (aq) 33Co(s) e) Hydrogen gas is bubbled through a solution of silver nitrate Since, hydrogen is placed above silver in the activity series, it is more reactive than silver. Hence, it will displace silver from its nitrate solution. The balanced chemical equation is: H2g) + 2AgNO (aq)3-------> 2HNO (aq) + 23(s) --------------

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##### ISBN: 9780321809247

Since the solution to 56E from 4 chapter was answered, more than 533 students have viewed the full step-by-step answer. The answer to “?What is the molarity of Cl- in each solution? a. 0.200 M NaCl b. 0.150 M SrCl2 c. 0.100 M AlCl3” is broken down into a number of easy to follow steps, and 21 words. The full step-by-step solution to problem: 56E from chapter: 4 was answered by , our top Chemistry solution expert on 02/22/17, 04:35PM. This full solution covers the following key subjects: solution, metal, added, nitrate, Write. This expansive textbook survival guide covers 82 chapters, and 9454 solutions. This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3. Chemistry: A Molecular Approach was written by and is associated to the ISBN: 9780321809247.

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