If 123 mL of a 1.1 M glucose solution is diluted to 500.0

Chapter 4, Problem 61E

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QUESTION:

Problem 61E

If 123 mL of a 1.1 M glucose solution is diluted to 500.0 mL, what is the molarity of the diluted solution?

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QUESTION:

Problem 61E

If 123 mL of a 1.1 M glucose solution is diluted to 500.0 mL, what is the molarity of the diluted solution?

ANSWER:

Solution 61E Solution: Here, we are going to calculate the molarity of the given solution. Also, we are going to calculate the number of moles of protons present in 350 mL of a 4.50 M solution of nitric acid and volume in millilitres of a 6.00 M NaOH solution needed to provide 0.350 mol of NaOH. Step1: Molarity is defined as the number of moles of the solute(Here ZuCl is the solute) in 1 litre of the 2 solution. Mathematically, Number of moles of solute Molarity(M) = -------------------------------------- ------(1) Volume of solution in litres Step2: a) Number of moles of ZuCl = 0.1752oles Volume of solution in li

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