What is the minimum amount of 6.0 M H2SO4 necessary to produce 25.0 g of H2 (g) according to the reaction between aluminum and sulfuric acid?

Solution: Here, we are going to calculate the mass of ethanol required to make 1.00 L of vodka. Also, we are going to calculate the volume of ethanol required to make 1.00 L of vodka. Step1: Molarity is defined as the number of moles of the solute(Here ethanol is the solute) in 1 litre of the solution. Mathematically, Number of moles of solute Molarity(M) = -------------------------------------- ------(1) Volume of solution in litres Step2: a) Given, molarity of the ethanol solution = 6.86 M Volume of the ethanol solution in Litres = 1.00 L Using the mathematical expression for molarity calculation, we get, number of moles of ethanol = Volume of solution...