# A 25.0 mL sample of a 1.20 M potassium chloride solution ## Problem 69E Chapter 4

Chemistry: A Molecular Approach | 3rd Edition

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Problem 69E

A 25.0 mL sample of a 1.20 M potassium chloride solution is mixed with 15.0 mL of a 0.900 M barium nitrate solution and this precipitation reaction occurs: The solid BaCl2 is collected, dried, and found to have a mass of 2.45 g. Determine the limiting reactant, the theoretical yield, and the percent yield.

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Solution: Here, we are going to identify the compound that will have highest concentration of potassium ion. Step1: a) 1 mole of KCl contains 1 mole of potassium(K ) ion + Therefore, 0.20 M KCL will contain 0.20 M K ion. + + Similarly, 0.15 M K CrO wil2conta4 (2 x 0.15 = 0.30) M K ion. And 0.080 M K PO will contain (3 x 0.080 = 0.24) M K ion. + 3 4 Thus, 0.15 M K CrO wi2 have4 ghest concentration of potassium ion. Step2: b) Number of moles of any compound in solution is given by: Number of moles of solute = Volume of solution in L X Molarity solute...

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##### ISBN: 9780321809247

This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3rd. The answer to “A 25.0 mL sample of a 1.20 M potassium chloride solution is mixed with 15.0 mL of a 0.900 M barium nitrate solution and this precipitation reaction occurs: The solid BaCl2 is collected, dried, and found to have a mass of 2.45 g. Determine the limiting reactant, the theoretical yield, and the percent yield.” is broken down into a number of easy to follow steps, and 54 words. Chemistry: A Molecular Approach was written by and is associated to the ISBN: 9780321809247. This full solution covers the following key subjects: ion, potassium, cro, concentration, Greater. This expansive textbook survival guide covers 82 chapters, and 9464 solutions. The full step-by-step solution to problem: 69E from chapter: 4 was answered by , our top Chemistry solution expert on 02/22/17, 04:35PM. Since the solution to 69E from 4 chapter was answered, more than 872 students have viewed the full step-by-step answer.

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