Problem 83E

Write balanced molecular and net ionic equations for the reaction between hydrobromic acid and potassium hydroxide.

Solution: Here, we are going to calculate the mass of sodium bicarbonate that must be added to neutralize 27 mL of 6.0 M sulfuric acid. Step1: Given, volume of H SO sol2ion4pilled = 27 mL = 27/1000 L = 0.027 L Molarity of H SO solution spilled = 6.0 M 2 4 Therefore, number of moles of H SO = Volume2f s4ution in litres X Molarity = 0.027 L X 6.0 M = 0.162 mol Step2: The sodium bicarbonate reacts with sulfuric acid according to: In the above equation, 1 mole of H SO requires 2 moles of NaHCO for complete neutralization. 2 4 3 Therefore, 0.162 moles of H SO will 2quir4(2 x 0.162 = 0.324) moles of NaHCO for 3 complete neutralization. Step3: Now, 1 mole of NaHCO = molar mas3of NaHCO 3 Therefore, 0.324 moles of NaHCO = 0.324 X molar mass of NaHCO 3 3 = 0.324 X 84.01 g [ molar mass of NaHCO = 84.01 3 g/mol] = 27.22 g Thus, the required mass of NaHCO is 27.22 g. 3