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Solved: Write balanced molecular and net ionic equations

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Problem 84E Chapter 4

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 84E

Write balanced molecular and net ionic equations for the reaction between nitric acid and calcium hydroxide.

Step-by-Step Solution:
Step 1 of 3

Solution: Here, we are going to calculate the mass of acetic acid that must be added to neutralize 42.5 mL of 0.115 M sodium hydroxide. Step1: Given, volume of NaOH solution used = 42.5 mL = 42.5/1000 L = 0.0425 L Molarity of NaOH solution used = 0.115 M Therefore, number of moles of NaOH = Volume of solution in litres X Molarity = 0.0425 L X 0.115 M = 0.005 mol Step2: Acetic acid reacts with sodium hydroxide according to the following way: CH C3H(aq) + NaOH(aq) ------> NaCH COO(aq) + H O 3 2 In the above equation, 1 mole of NaOH requires 1 mole of CH COOH for complete 3 neutralization....

Step 2 of 3

Chapter 4, Problem 84E is Solved
Step 3 of 3

Textbook: Chemistry: A Molecular Approach
Edition: 3rd
Author: Nivaldo J. Tro
ISBN: 9780321809247

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