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Get Full Access to Calculus: Early Transcendental Functions - 6 Edition - Chapter 13.1 - Problem 18
Get Full Access to Calculus: Early Transcendental Functions - 6 Edition - Chapter 13.1 - Problem 18

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# ?In Exercises 7-18, find and simplify the function values. $$f(x, y)=3 x^{2}-2 y$$ (a) $$\frac{f(x+\Delta x, y)-f(x, y)}{\Delta x}$$ ISBN: 9781285774770 141

## Solution for problem 18 Chapter 13.1

Calculus: Early Transcendental Functions | 6th Edition

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Problem 18

In Exercises 7-18, find and simplify the function values.

$$f(x, y)=3 x^{2}-2 y$$

(a) $$\frac{f(x+\Delta x, y)-f(x, y)}{\Delta x}$$

(b) $$\frac{f(x, y+\Delta y)-f(x, y)}{\Delta y}$$

Text Transcription:

f(x, y) = 3x^2 - 2y

f(x + Delta x, y) - f(x, y) / Delta x

f(x, y + Delta y) - f(x, y) / Delta y

Step-by-Step Solution:

Step 1 of 5) converges. To see this, we ignore the first three terms and compare the remaining terms with those of the convergent geometric series gqn =0(1>2n). The term 1>12n + 2n2 of the truncated sequence is less than the corresponding term 1>2n of the geometric series. We see that term by term we have the comparison

Step 2 of 2

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?In Exercises 7-18, find and simplify the function values. $$f(x, y)=3 x^{2}-2 y$$ (a) $$\frac{f(x+\Delta x, y)-f(x, y)}{\Delta x}$$