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: Lanthanum metal forms cations with a charge of 3+.

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 98 Chapter 4

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 98

98: Lanthanum metal forms cations with a charge of 3+. Consider the following observations about the chemistry of lanthanum: When lanthanum metal is exposed to air, a white solid (compound A) is formed that contains lanthanum and one other element. When lanthanum metal is added to water, gas bubbles are observed and a different white solid (compound B) is formed. Both A and B dissolve in hydrochloric acid to give a clear solution. When either of these solutions is evaporated, a soluble white solid (compound C) remains. If compound C is dissolved in water and sulfuric acid is added, a white precipitate (compound D) forms, (a) Propose identities for the substances A, B, C, and D. (b) Write net ionic equations for all the reactions described. (c) Based on the preceding observations, what can be said about the position of lanthanum in the activity series (Table)? Table Activity Series of Metals in Aqueous Solution

Step-by-Step Solution:
Step 1 of 3

Solution: Here, we are going to identify the compounds A, B, C and D and also write the net ionic equations for all the reactions described. Step1: When, lanthanum is exposed to air, lanthanum oxide is formed. The balanced molecular equation for the reaction is: 4Ln(s) + 3O (g) --2--> 2Ln O 2 3 The compound (A) thus formed is Ln O 2 3 Step2: When lanthanum metal is added to water, lanthanum hydroxide is formed. The balanced molecular equation for the reaction is: 2Ln(s) + 6H O(l) -2---> 2Ln(OH) (s) + 3H (g) 3 2 The compound (B) thus formed is Ln(OH) 3 Step3: Both the compounds A and B dissolves in HCl as shown below: Ln O2(s3+ 6HCl(aq) -------> 2LnCl (aq) + 3H O 3 2 Ln(OH) (s) +3HCl(aq) -------> LnCl (aq) + 3H O 3 2 The net ionic equation for...

Step 2 of 3

Chapter 4, Problem 98 is Solved
Step 3 of 3

Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

Since the solution to 98 from 4 chapter was answered, more than 436 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 98 from chapter: 4 was answered by , our top Chemistry solution expert on 02/22/17, 04:35PM. This full solution covers the following key subjects: lanthanum, compound, white, solid, metal. This expansive textbook survival guide covers 82 chapters, and 9464 solutions. Chemistry: A Molecular Approach was written by and is associated to the ISBN: 9780321809247. This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3. The answer to “98: Lanthanum metal forms cations with a charge of 3+. Consider the following observations about the chemistry of lanthanum: When lanthanum metal is exposed to air, a white solid (compound A) is formed that contains lanthanum and one other element. When lanthanum metal is added to water, gas bubbles are observed and a different white solid (compound B) is formed. Both A and B dissolve in hydrochloric acid to give a clear solution. When either of these solutions is evaporated, a soluble white solid (compound C) remains. If compound C is dissolved in water and sulfuric acid is added, a white precipitate (compound D) forms, (a) Propose identities for the substances A, B, C, and D. (b) Write net ionic equations for all the reactions described. (c) Based on the preceding observations, what can be said about the position of lanthanum in the activity series (Table)? Table Activity Series of Metals in Aqueous Solution” is broken down into a number of easy to follow steps, and 154 words.

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