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: Hard water contains Ca2+, Mg2+, and Fe2+, which

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 101 Chapter 4

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 101

101: Hard water contains Ca2+, Mg2+, and Fe2+, which interfere with the action of soap and leave an insoluble coating on the insides of containers and pipes when heated. Water softeners replace these ions with Na+. Keep in mind that charge balance must be maintained, (a) If 1500 L of hard water contains 0.020 M Ca2+ and 0.0040 M Mg2+, how many moles of Na+ is needed to replace these ions? (b) If the sodium is added to the water softener in the form of NaCI, how many grams of sodium chloride are needed?

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Solution 101: Solution: Here, we are going to calculate the number of moles of sodium ion required replace 0.020 M calcium ions and 0.0040 M magnesium ions. Step1: a) Given, volume of hard water = 1500 L Molarity of calcium ion = 0.020 M MOlarity of magnesium ion = 0.0040 M Therefore number of moles of calcium ions = Volume of water in litres X Molarity = 1500 L X 0.020 M = 30 mol Number of moles of magnesium ions = 1500 L X 0.0040 M = 6 mol Step2: Total number of moles of calcium and magnesium ions in water = 30 + 6 = 36 mol Since, both magnesium and calcium...

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Chapter 4, Problem 101 is Solved
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Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

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