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?In Exercises 1 - 10, evaluate the integral. \(\int_{x^{3}}^{\sqrt{x}}\left(x^{2}+3 y^{2}\right) d y\)

Calculus: Early Transcendental Functions | 6th Edition | ISBN: 9781285774770 | Authors: Ron Larson ISBN: 9781285774770 141

Solution for problem 6 Chapter 14.1

Calculus: Early Transcendental Functions | 6th Edition

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Calculus: Early Transcendental Functions | 6th Edition | ISBN: 9781285774770 | Authors: Ron Larson

Calculus: Early Transcendental Functions | 6th Edition

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Problem 6

In Exercises 1 - 10, evaluate the integral.

\(\int_{x^{3}}^{\sqrt{x}}\left(x^{2}+3 y^{2}\right) d y\)

Text Transcription:

int_{x^3}^{sqrt{x}} (x^2 + 3y^2) dy

Step-by-Step Solution:

Step 1 of 5) Figure 11.14 (a) The vector u - v, when added to v, gives u. (b) u - v = u + (-v).

Step 2 of 2

Chapter 14.1, Problem 6 is Solved
Textbook: Calculus: Early Transcendental Functions
Edition: 6
Author: Ron Larson
ISBN: 9781285774770

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?In Exercises 1 - 10, evaluate the integral. \(\int_{x^{3}}^{\sqrt{x}}\left(x^{2}+3 y^{2}\right) d y\)