The complete combustion of octane, C8H18, the main component of gasoline, proceeds as
Chapter 3, Problem 3.64(choose chapter or problem)
The complete combustion of octane, C8H18, the main component of gasoline, proceeds as follows: 2 C8H18(1) + 25 02(g) ----> 16 C02(g) + 18 H20(g) (a) How many moles of 02 are needed to burn 1.25 mol of C8H18? (b) How many grams of 02 are needed to burn 10.0 g of CaHta? (c) Octane has a density of 0.692 g/mL at 20 oc. How many grams of 02 are required to burn 1 .00 gal of CaH1a?
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer