When benzene (C6H6) reacts with bromine (Br2), bromobenzene (C6H5Br) is obtained: C6H6 +

Chapter 3, Problem 3.77

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When benzene (C6H6) reacts with bromine (Br2), bromobenzene (C6H5Br) is obtained: C6H6 + Brz -----> C6HsBr + HBr (a) What is the theoretical yield of bromo benzene in this reaction when 30.0 g of benzene reacts with 65.0 g of bromine? (b) If the actual yield of bromobenzene was 42.3 g, what was the percentage yield?

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