When 0.55 g of pure benzoic acid (C6H5COOH) is dissolved in 32.0 g of benzene (C6H6)
Chapter 13, Problem 13.112(choose chapter or problem)
When 0.55 g of pure benzoic acid (C6H5COOH) is dissolved in 32.0 g of benzene (C6H6), the freezing point of the solution is 0.36 'C lower than the freezing point value of 5.5 'C for the pure solvent. (a) Calculate the molecular weight of benzoic acid in benzene. (b) Use the structure of the solute to account for the observed value:
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer