A flask is charged with 1.500 atm of N204(g) and 1.00 atm N02(g) at 25 'C, and the

Chapter 15, Problem 15.34

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A flask is charged with 1.500 atm of N204(g) and 1.00 atm N02(g) at 25 'C, and the following equilibrium is achieved: N204(g) = 2 N02(g) After equilibrium is reached, the partial pressure of N02 is 0.512 atm. (a) What is the equilibrium partial pressure of N204? (b) Calculate the value of Kp for the reaction.

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