Solution Found!
We separate uranium-235 from U-238 by fluorinating a sample of uranium to form UF6
Chapter 5, Problem 85(choose chapter or problem)
We separate uranium-235 from U-238 by fluorinating a sample of uranium to form \(\mathrm{UF}_{6}\) (which is a gas) and then taking advantage of the different rates of effusion and diffusion for compounds containing the two isotopes. Calculate the ratio of effusion rates for \({ }^{238} \mathrm{UF}_{6}\) and \({ }^{235} \mathrm{UF}_{6}\). The atomic mass of U-235 is 235.054 amu and that of U-238 is 238.051 amu.
Questions & Answers
QUESTION:
We separate uranium-235 from U-238 by fluorinating a sample of uranium to form \(\mathrm{UF}_{6}\) (which is a gas) and then taking advantage of the different rates of effusion and diffusion for compounds containing the two isotopes. Calculate the ratio of effusion rates for \({ }^{238} \mathrm{UF}_{6}\) and \({ }^{235} \mathrm{UF}_{6}\). The atomic mass of U-235 is 235.054 amu and that of U-238 is 238.051 amu.
ANSWER:Step 1 of 2
Given Data:
*The molar mass of U-238 is 238.051 amu.
*The molar mass of U-235 is 235.054 amu.
The Graham law describes the relation between molar masses and rates.
