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The kinetic energy of a rolling billiard ball is given by KE = 1 >2mv2 . Suppose a 0.17
Chapter 6, Problem 97(choose chapter or problem)
The kinetic energy of a rolling billiard ball is given by KE = 1 >2mv2 . Suppose a 0.17 kg billiard ball is rolling down a pool table with an initial speed of 4.5 m/s. As it travels, it loses some of its energy as heat. The ball slows down to 3.8 m/s and then collides head-on with a second billiard ball of equal mass. The first billiard ball completely stops and the second one rolls away with a velocity of 3.8 m/s. Assume the first billiard ball is the system and calculate w , q , and E for the process.
Questions & Answers
QUESTION:
The kinetic energy of a rolling billiard ball is given by KE = 1 >2mv2 . Suppose a 0.17 kg billiard ball is rolling down a pool table with an initial speed of 4.5 m/s. As it travels, it loses some of its energy as heat. The ball slows down to 3.8 m/s and then collides head-on with a second billiard ball of equal mass. The first billiard ball completely stops and the second one rolls away with a velocity of 3.8 m/s. Assume the first billiard ball is the system and calculate w , q , and E for the process.
ANSWER:Problem 97The kinetic energy of a rolling billiard ball is given by . Suppose a 0.17 kg abilliard ball is rolling down a pool table with an initial speed of 4.5 m/s. As it travels, itloses some of its energy as heat. The ball slows down to 3.8 m/s and then collides head-on with a second billiard ball of equal mass. The first billiard ball completely stops andthe second one rolls away with a velocity of 3.8 m/s. Assume the first billiard ball is thesystem and calculate w,q, and E for the process. Step by step solutionStep 1 of 4We know that the internal energy of a system is the sum of its kinetic and potential energies ofall of the particles that compose the system. Internal energy is a state function. Internal energyvalue depends on the state of the system.From the given,Mass of the billiard ball =0.17 kgInitial speed of the billiard ball = 4.5 m / sCollision speed =3.8 m /s