Consider the simple one-step reaction: A( g ) m B( g ) Since the reaction occurs in a
Chapter 14, Problem 104(choose chapter or problem)
Consider the simple one-step reaction: A( g ) m B( g ) Since the reaction occurs in a single step, the forward reaction has a rate of kfor [A] and the reverse reaction has a rate of krev [B]. What happens to the rate of the forward reaction when we increase the concentration of A? How does this explain the reason behind Le Chteliers principle?
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