A Cu>Cu2+ concentration cell has a voltage of 0.22 V at 25 C. The concentration of Cu2+
Chapter 18, Problem 82(choose chapter or problem)
A \(\mathrm{Cu} / \mathrm{Cu}^{2+}\) concentration cell has a voltage of 0.22 V at \(25\ ^{\circ}\mathrm{C}\). The concentration of \(\mathrm{Cu}^{2+}\) in one of the half-cells is \(1.5\times10^{-3}\mathrm{\ M}\). What is the concentration of \(\mathrm{Cu}^{2+}\) in the other half-cell? (Assume the concentration in the unknown cell to be the lower of the two concentrations.)
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