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Solved: Use the heat equation to calculate the energy, in joules and calories, for each
Chapter 0, Problem 3.37(choose chapter or problem)
Use the heat equation to calculate the energy, in joules and calories, for each of the following (see Table 3.11):
a. to heat 25.0 g of water from 12.5 °C to 25.7 °C
b. to heat 38.0 g of copper from 122 °C to 246 °C
c. lost when 15.0 g of ethanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\), cools from 60.5 °C to -42.0 °C
d. lost when 125 g of iron cools from 118 °C to 55 °C
Questions & Answers
QUESTION:
Use the heat equation to calculate the energy, in joules and calories, for each of the following (see Table 3.11):
a. to heat 25.0 g of water from 12.5 °C to 25.7 °C
b. to heat 38.0 g of copper from 122 °C to 246 °C
c. lost when 15.0 g of ethanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\), cools from 60.5 °C to -42.0 °C
d. lost when 125 g of iron cools from 118 °C to 55 °C
ANSWER:Step 1 of 5
The physical property termed as specific heat is used to explain about the energy requirements of several substances. The quantity of heat needed to elevate the temperature of 1 g of a specific substance is referred to as the specific heat (SH).
The heat lost or gained by a particular substance can be obtained using the formula:
Where,
m denotes the mass of the substance.
C denotes the specific heat capacity.
denotes the change in temperature.