Solution Found!
Calculate each of the following quantities in 0.185 mole of C6H14O: a. moles of C b
Chapter 0, Problem 7.6(choose chapter or problem)
Calculate each of the following quantities in 0.185 mole of \(\mathrm{C}_{6} \mathrm{H}_{14} \mathrm{O}:\)
a. moles of \(\mathrm{C}\)
b. moles of \(\mathrm{O}\)
c. atoms of \(\mathrm{H}\)
d. atoms of \(\mathrm{C}\)
Questions & Answers
QUESTION:
Calculate each of the following quantities in 0.185 mole of \(\mathrm{C}_{6} \mathrm{H}_{14} \mathrm{O}:\)
a. moles of \(\mathrm{C}\)
b. moles of \(\mathrm{O}\)
c. atoms of \(\mathrm{H}\)
d. atoms of \(\mathrm{C}\)
ANSWER:Step 1 of 5
a)
A mole is a unit that contains \(6.02 \times 10^{23}\) particles. The mass of one mole of an element is equal to its atomic weight. The molar mass is the mass of one mole of molecules.
Here, we are given the moles of \(\mathrm{C}_{6} \mathrm{H}_{14} \mathrm{O}\) and we need to find the mole of carbon (C).