Fruit Selection On a lunch counter, there are 3 oranges. 5

Step 1 of 2

We have to find the probability of selecting 1 orange, 1 apple, and 1 banana 

There are 3 oranges, 5 apples, and 2 bananas

The total no.of fruits = 3 + 5 + 2

                                  = 10

The no.of ways of selecting 3 fruits from all the fruits

\(\begin{array}{l} ={ }_{10} C_{3} \\ =120 \end{array}\)

The no.of ways of selecting 1 orange, 1 apple, and 1 banana is 

\(\left(\begin{array}{l} 3 \\ 1 \end{array}\right) \times\left(\begin{array}{l} 5 \\ 1 \end{array}\right) \times\left(\begin{array}{l} 2 \\ 1 \end{array}\right)=30\)