Solution Found!
The formula for finding the variance for a probability
Chapter 5, Problem 22EC(choose chapter or problem)
The formula for finding the variance for a probability distribution is
\(\sigma^{2}=\Sigma\left[(X-\mu)^{2} \cdot P(X)\right]\)
Verify algebraically that this formula gives the same result as the shortcut formula shown in this section.
Equation Transcription:
Text Transcription:
\sigma^{2}=\Sigma\left[(X-\mu)^{2} \cdot P(X)\right]
Questions & Answers
QUESTION:
The formula for finding the variance for a probability distribution is
\(\sigma^{2}=\Sigma\left[(X-\mu)^{2} \cdot P(X)\right]\)
Verify algebraically that this formula gives the same result as the shortcut formula shown in this section.
Equation Transcription:
Text Transcription:
\sigma^{2}=\Sigma\left[(X-\mu)^{2} \cdot P(X)\right]
ANSWER:Solution 22EC
Step1 of 2:
From the given problem we have the formula for finding the variance for a probability distribution is:
We need to verify algebraically that this formula gives the same result as the shortcut formula shown in this section.
Step2 of 2:
We have,
The shortcut formula is: