Which compound is likely to have an incomplete octet?
Step-by-step solution Step 1 of 5 Atoms have the tendency to share (as it happens in covalent bond between non metallic species) or transfer (as it happens in ionic bond between a metal and a non metal specie) electrons in order to attain a more stable electron configuration. After the bond establishes, there have to be 8 electrons in the outer shell surrounding every element in order to respect the octet rule. The electrons surrounding an element can be or in form of “lone pair” (a couple of electrons that are not involved in any bond) or in form of shared electron (in this case there is a line connecting If we use the Lewis structure, it’s only a matter of counting the electrons surrounding every atom. We are going to demonstrate the answer we need is letter d) Step 2 of 5 (a) Ammonia : The Lewis structure of ammonia is as follows: From the Lewis structure of ammonia, N has 8 electrons in the outermost shell. Therefore, it has complete octet. Even the Hydrogen atoms reach the stability because everyone owns 2 electrons thanks to the fact they are shared with Nitrogen in a covalent bond. Step 3 of 5 (b) Sulfur trioxide : The Lewis structure of sulfur trioxide is as follows: From the Lewis structure of sulfur trioxide, S has 8 electrons in the outermost shell. Even Oxygen atoms reach the stability because everyone owns 8 .