What is the magnitude of the dipole moment formed by separating a proton and an electron by 100 pm? 200 pm?

Solution 23 Step 1 of 2 -19 First we have to consider that a proton has a charge q= 1.6 x 10 C For a distance 100 pm= 100 x 10 -1m thus = q *r= (1.6 x 10 -19C) x (100 x 10 -12m)= 1.6 x 10 -29C x m Since 1D= 3.34 x 10 -30C x m If we want to find the value of thus = 4.79 D