Draw the Lewis structure for nitric acid (the hydrogen atom is attached to one of the oxygen atoms). Include all three resonance structures by alternating the double bond among the three oxygen atoms. Use formal charge to determine which of the resonance structures is most important to the structure of nitric acid.
Solution 95E Step 1 of of 6 The molecule HNO formed by Nitrogen(Electronegativity=3.0) , Oxygen (Electronegativity=3.5) and Hydrogen (electronegativity= 2.2) In order to design this molecule, we have to put N at the center, the two atoms of Oxygen at its left, right and upper side. The H goes to the side of one atom of H. Step 2 of 6 N belongs to V A group, thus we have 5 valence electrons O belongs to VI A group, thus we have 6 valence electrons H belongs to I A group, thus we have 1 valence electrons By applying the formula Total electrons= (Valence electrons in N) + 3(Valence electrons in O) + (Valence electrons in H) = 5 +3(6)+ 1= 24 Step 3 of 6 We give the bonding electrons to each pair of atoms we used 8 electrons