Solution Found!
Answer: In each equation, label the acids, bases, and conjugate pairs: (a) (b) (c)
Chapter 18, Problem 18.47(choose chapter or problem)
In each equation, label the acids, bases, and conjugate pairs:
(a) \(\mathrm{HCl}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{Cl}^{-}+\mathrm{H}_{3} \mathrm{O}^{+}\)
(b) \(\mathrm{HClO}_{4}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightleftharpoons \mathrm{ClO}_{4}^{-}+\mathrm{H}_{3} \mathrm{SO}_{4}^{+}\)
(c) \(\mathrm{HPO}_{4}^{2-}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightleftharpoons \mathrm{H}_{2} \mathrm{PO}_{4}^{-}+\mathrm{HSO}_{4}^{-}\)
Questions & Answers
QUESTION:
In each equation, label the acids, bases, and conjugate pairs:
(a) \(\mathrm{HCl}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{Cl}^{-}+\mathrm{H}_{3} \mathrm{O}^{+}\)
(b) \(\mathrm{HClO}_{4}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightleftharpoons \mathrm{ClO}_{4}^{-}+\mathrm{H}_{3} \mathrm{SO}_{4}^{+}\)
(c) \(\mathrm{HPO}_{4}^{2-}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightleftharpoons \mathrm{H}_{2} \mathrm{PO}_{4}^{-}+\mathrm{HSO}_{4}^{-}\)
ANSWER:Step 1 of 4
Bronsted-Lowry acid is that substance which donates protons to base. After loss of proton Bronsted-Lowry acid gives corresponding conjugate base and base after gain of proton gives conjugate acid.