Aluminum hydroxide reacts with sulfuric acid as follows: 2
Chapter , Problem 3.78(choose chapter or problem)
Aluminum hydroxide reacts with sulfuric acid as follows: 2 Al1OH231s2 + 3 H2SO41aq2 Al21SO4231aq2 + 6 H2O1l2 Which is the limiting reactant when 0.500 mol Al1OH23 and 0.500 mol H2SO4 are allowed to react? How many moles of Al21SO423 can form under these conditions? How many moles of the excess reactant remain after the completion of the reaction?
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