Solution Found!
The position of a particle moving in an r xy plane is
Chapter , Problem 11(choose chapter or problem)
The position \(\vec{r}\) of a particle moving in an xy plane is given by \(\vec{r}=\left(2.00 t^{3}-5.00 t\right) \hat{\mathrm{i}}+\left(6.00-7.00 t^{4}\right) \hat{j}\), with \(\vec{r}\) in meters and t in seconds. In unit-vector notation, calculate
(a) \(\vec{r}\),
(b) \(\vec{v}\), and
(c) \(\vec{a}\) for t = 2.00 s.
(d) What is the angle between the positive direction of the x axis and a line tangent to the particle’s path at t = 2.00 s?
Questions & Answers
QUESTION:
The position \(\vec{r}\) of a particle moving in an xy plane is given by \(\vec{r}=\left(2.00 t^{3}-5.00 t\right) \hat{\mathrm{i}}+\left(6.00-7.00 t^{4}\right) \hat{j}\), with \(\vec{r}\) in meters and t in seconds. In unit-vector notation, calculate
(a) \(\vec{r}\),
(b) \(\vec{v}\), and
(c) \(\vec{a}\) for t = 2.00 s.
(d) What is the angle between the positive direction of the x axis and a line tangent to the particle’s path at t = 2.00 s?
ANSWER:Step 1 of 5
Given data
Position vector of the particle as a function of time is 
Time 