Explain the difference between a pure substance and a

Solution 11E: The average value can be calculated as follows 3.15 + 3.12+ 2.98+3.14+3.02+3.09 Thus, the average weight of each bean is = 6 = 18.5 6 = 3.08 g Total weight of the jar having all beans = 2082 g. Weight of empty Jar =6 53 g Thus, weight of all beans =Total weight of the jar having all beans - Weight of empty Jar = 2082 g- 653 g = 1429 g Therefore, Total number of beans in the jar will be Total weight of beans = Average weight of each bean = 1429 g 3.08 g = 463.96 = 464 (significant figures rounded off to 3, this is because...