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Get Full Access to College Physics For Ap® Courses - 1 Edition - Chapter 18 - Problem 60
Get Full Access to College Physics For Ap® Courses - 1 Edition - Chapter 18 - Problem 60

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# Integrated Concepts A 5.00 g charged insulating ball hangs on a 30.0 cm long string in a

ISBN: 9781938168932 372

## Solution for problem 60 Chapter 18

College Physics for AP® Courses | 1st Edition

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Problem 60

Integrated Concepts A 5.00 g charged insulating ball hangs on a 30.0 cm long string in a uniform horizontal electric field as shown in Figure 18.56. Given the charge on the ball is 1.00 C , find the strength of the field.

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Physics 2 for Engineering Week 9 Magnetic Field and Forces B – Magnetic field FB– Magnetic force Moving charge q ge1erates a magnetic field B, which exerts F on anBther moving charge q 2 FB= q v x B With charge q, velocity v, magnetic field generated B, and magnetic force exerted F B Unit of B is Tesla (T); 1 Tesla = 1 N/Am = 10 Gauss FBis perpendicular to both v and B Motion of charged particles in magnetic field 2 FBis a centripetal force; FB= q v B = m v R Radius of orbit R = m v / q B where v is perpendicular to B Time Period = 2 π R / v; Angular velocity ω = v / R = q B / m Dots = vector pointing out of plane; crosses = pointing into plane In presence of E and B field, F = F B F E Magnetic flux Φ = B x A if B is uniform/constant; Φ = ∫ B x dA if B is non-uniform/variable 2 Unit of magnetic flux is Weber, 1 Wb = 1 Tm ; scalar quantity Area vector is perpendicular to surface A; on closed surface A points out Magnetism A x B = ABsinθ A = A x + A jy+ A kz i x j = k j x i = -k j x k = i k x j = -i k x i = j i x k = -j Along a wire, F = I l x B = I l B sin θ Coil- loops are called turns Dipole magnetic moment μ = I A (where A is area of loop/turn); τ = μ x B = I B A sin θ

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##### ISBN: 9781938168932

The answer to “Integrated Concepts A 5.00 g charged insulating ball hangs on a 30.0 cm long string in a uniform horizontal electric field as shown in Figure 18.56. Given the charge on the ball is 1.00 C , find the strength of the field.” is broken down into a number of easy to follow steps, and 42 words. This full solution covers the following key subjects: . This expansive textbook survival guide covers 34 chapters, and 2282 solutions. The full step-by-step solution to problem: 60 from chapter: 18 was answered by , our top Physics solution expert on 03/09/18, 08:07PM. College Physics for AP® Courses was written by and is associated to the ISBN: 9781938168932. This textbook survival guide was created for the textbook: College Physics for AP® Courses, edition: 1. Since the solution to 60 from 18 chapter was answered, more than 396 students have viewed the full step-by-step answer.

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