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To obtain the most precise value of BE from the equation BE= ZM 1 H + Nmn c2 m A X c2

College Physics for AP® Courses | 1st Edition | ISBN: 9781938168932 | Authors: Gregg Wolfe, Irina Lyublinskaya, Douglas Ingram ISBN: 9781938168932 372

Solution for problem 23 Chapter 31

College Physics for AP® Courses | 1st Edition

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College Physics for AP® Courses | 1st Edition | ISBN: 9781938168932 | Authors: Gregg Wolfe, Irina Lyublinskaya, Douglas Ingram

College Physics for AP® Courses | 1st Edition

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Problem 23

To obtain the most precise value of BE from the equation BE= ZM 1 H + Nmn c2 m A X c2 , we should take into account the binding energy of the electrons in the neutral atoms. Will doing this produce a larger or smaller value for BE? Why is this effect usually negligible?

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tran (mmt2449) – Homework 05 – yao – (56695) 1 This print-out should have 26 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. θ 001 10.0 points F2 F Three 7 kg masses are located at points in the xy plane. F1 The magnitude of the resultant force is q F = F + F 2 59 cm h 1 2 −8 2 = (1.6146 × 10 N) i −9 2 1/2 + (9.39263 × 10 N) 45 cm = 1.86793 × 10−8 N . What is the magnitude of the resultant force (caused by the other two masses) on 002 10.0 points the mass at the origin The universal gravita-The planet Krypton has a mass of tional constant is 6.6726 × 10 N ▯ m /kg . 5.3 × 103 kg and radius of 1.3 × 10 m.

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Chapter 31, Problem 23 is Solved
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Textbook: College Physics for AP® Courses
Edition: 1
Author: Gregg Wolfe, Irina Lyublinskaya, Douglas Ingram
ISBN: 9781938168932

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To obtain the most precise value of BE from the equation BE= ZM 1 H + Nmn c2 m A X c2