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A force of 35.0 N is required to start a 6.0-kg box moving
Chapter 4, Problem 37(choose chapter or problem)
QUESTION:
A force of 35.0 N is required to start a 6.0-kg box moving across a horizontal concrete floor.
(a) What is the coefficient of static friction between the box and the floor?
(b) If the 35.0-N force continues, the box accelerates at \(0.60 \mathrm{~m} / \mathrm{s}^{2}\). What is the coefficient of kinetic friction?
Questions & Answers
QUESTION:
A force of 35.0 N is required to start a 6.0-kg box moving across a horizontal concrete floor.
(a) What is the coefficient of static friction between the box and the floor?
(b) If the 35.0-N force continues, the box accelerates at \(0.60 \mathrm{~m} / \mathrm{s}^{2}\). What is the coefficient of kinetic friction?
ANSWER:Step 1of 3
We need to first draw the freebody diagram: