A force of 35.0 N is required to start a 6.0-kg box moving

Chapter 4, Problem 37

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QUESTION:

A force of 35.0 N is required to start a 6.0-kg box moving across a horizontal concrete floor.

(a) What is the coefficient of static friction between the box and the floor?

(b) If the 35.0-N force continues, the box accelerates at \(0.60 \mathrm{~m} / \mathrm{s}^{2}\). What is the coefficient of kinetic friction?

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QUESTION:

A force of 35.0 N is required to start a 6.0-kg box moving across a horizontal concrete floor.

(a) What is the coefficient of static friction between the box and the floor?

(b) If the 35.0-N force continues, the box accelerates at \(0.60 \mathrm{~m} / \mathrm{s}^{2}\). What is the coefficient of kinetic friction?

ANSWER:

Step 1of 3

We need to first draw the freebody diagram:

  

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