Solution: The normal form (5) of an nth-order differential equation is equivalent to (4)
Chapter 1, Problem 53(choose chapter or problem)
The normal form (5) of an nth-order differential equation is equivalent to (4) whenever both forms have exactly the same solutions. Make up a first-order differential equation for which F(x, y, y) 0 is not equivalent to the normal form dydx f(x, y).
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