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Solved: A popular kitchen appliance produces
Chapter , Problem 6.2(choose chapter or problem)
A popular kitchen appliance produces electromagnetic radiation with a frequency of 2450 MHz. With reference to Figure 6.4, answer the following: (a) Estimate the wavelength of this radiation. (b) Would the radiation produced by the appliance be visible to the human eye? (c) If the radiation is not visible, do photons of this radiation have more or less energy than photons of visible light? (d) Which of the following is the appliance likely to be? (i) A toaster oven, (ii) A microwave oven, or (iii) An electric hotplate. [Section 6.1]
Questions & Answers
QUESTION:
A popular kitchen appliance produces electromagnetic radiation with a frequency of 2450 MHz. With reference to Figure 6.4, answer the following: (a) Estimate the wavelength of this radiation. (b) Would the radiation produced by the appliance be visible to the human eye? (c) If the radiation is not visible, do photons of this radiation have more or less energy than photons of visible light? (d) Which of the following is the appliance likely to be? (i) A toaster oven, (ii) A microwave oven, or (iii) An electric hotplate. [Section 6.1]
ANSWER:
Step 1 of 3
a)
Wavelength of electromagnetic radiation, \(\lambda\) is,
\(\lambda=\frac{c}{\nu}\)
Here, \(c\) is the speed of light and \(\nu\) is the frequency.
Convert the frequency into seconds as shown below.
\(1 \mathrm{MHz}=10^{6} \mathrm{sec}^{-1}\)
\(2450 \mathrm{MHz}=\frac{2450 \mathrm{MHz} \times 10^{6} \mathrm{sec}^{-1}}{1 \mathrm{MHz}}\)
\(=2450 \times 10^{6} \mathrm{sec}^{-1}\)