A particular coal contains 2.5% sulfur by mass. When this coal is burned at a power plant, the sulfur is converted into sulfur dioxide gas, which is a pollutant. To reduce sulfur dioxide emissions, calcium oxide (lime) is used. The sulfur dioxide reacts with calcium oxide to form solid calcium sulfite.: (a) Write the balanced chemical equation for the reaction., (b) If the coal is burned in a power plant that uses 2000 tons of coal per day, what mass of calcium oxide is required daily to eliminate the sulfur dioxide?, (c) How many grams of calcium sulfite are produced daily by this power plant?
Answer : Step 1 (a)given in the question that sulfur reacts with oxygen to give sulfur dioxide. The equation can be written as S(s)+O2(g)SO2(g) This sulfur dioxide gas is reacted with calcium oxide to form calcium sulfite . SO2(g)+CaO(s)CaSO3(s). Step 2 (b) oming to reactions taking place in combustion of coal are First sulfur in coal reacts with oxygen to form sulfur dioxide . S(s)+O2(g)SO2(g). The calcium oxide reacts with CaO it produces CaSO3. SO2(g)+CaO(s)CaSO3(s). When we see the above reactions we can understand that one mole of sulfur dioxide and calcium oxide to give calcium sulfite. Therefore 2000 ton =2*10 kg . 9 =2*10 g. Since 1 ton =1000kg 1kg =100g. As we know that coal contains 2.5% of sulfur by mass. The molar mass of sulfur present in 100 of coal=2.5g. So amount of sulfur present in 2*10 g of coal is =2.5g /100g*2*10 . 9 7 = 5.0 *10 g. Number of moles of sulfur contains in 5.0 *10 g of sulfur is 6 =1.56*10 mol .