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Complete and balance each acid–base equation.

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 85E Chapter 4

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 85E

Complete and balance each acid–base equation.

a. H2SO4(aq) + Ca(OH)2(aq) → 

b. HClO4(aq) + KOH(aq) →

c. H2SO4(aq) + NaOH(aq) →

Step-by-Step Solution:
Step 1 of 3

Solution: Here, we are going to calculate the molar mass of the metal hydroxide used in the above titration. Also, we are going to identify the alkali metal cation in the metal hydroxide used. Step1: a) Given, molarity of the hydrochloric acid used = 2.50 M Volume of the hydrochloric acid used = 17.0 mL = 17 / 1000 L = 0.017 L Therefore, number of moles of hydrochloric acid used = volume of the solution in litres X molarity = 0.017 L X 2.50 M = 0.0425 mol Step2: Since, alkali metal forms monohydroxide, 1 mole of HCl will be required to neutralize 1 mole of the alkali metal hydroxide. Thus, to neutralize 0.0425 mol of HCl, 0.0425 moles of alkali metal hydroxide will be required. Now, Number of moles of the metal hydroxide = mass of the metal hydroxide / molar mass Putting the values in the above equation, we get, 0.0425 mol = 4.36 g / molar mass Molar mass = 4.36 g / 0.0425 mol = 102.59 g/mol Thus, molar mass of the alkali metal hydroxide is 102.59 g/mol Step3: b) Molar mass of the hydroxyl group(OH) = (1 x atomic mass of O) + (1 x atomic mass of H) = (1 x 15.9994) + (1 x 1.0079) = 15.9994 + 1.0079 = 17.01 g/mol Therefore, molar mass of the alkali metal cation = molar mass of the alkali metal hydroxide - molar mass of the hydroxyl group = 102.59 g/mol - 17.01 g/mol = 85.58 g/mol Out of all the alkali metals, Rubidium has an atomic mass equal to 85.46 u. Thus, the alkali metal cation in the hydroxide is Rb . ------------------

Step 2 of 3

Chapter 4, Problem 85E is Solved
Step 3 of 3

Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

Since the solution to 85E from 4 chapter was answered, more than 390 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3. Chemistry: A Molecular Approach was written by and is associated to the ISBN: 9780321809247. The full step-by-step solution to problem: 85E from chapter: 4 was answered by , our top Chemistry solution expert on 02/22/17, 04:35PM. The answer to “?Complete and balance each acid–base equation. a. H2SO4(aq) + Ca(OH)2(aq) ? b. HClO4(aq) + KOH(aq) ? c. H2SO4(aq) + NaOH(aq) ?” is broken down into a number of easy to follow steps, and 21 words. This full solution covers the following key subjects: solution, metal, acid, added, alkali. This expansive textbook survival guide covers 82 chapters, and 9454 solutions.

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Complete and balance each acid–base equation.