Solution Found!
Let C = D = {3, 2, 1, 1, 2, 3} and define a relation S from C to D as follows: For all
Chapter 1, Problem 2(choose chapter or problem)
Let C = D = {−3,−2,−1, 1, 2, 3} and define a relation S from C to D as follows: For all \((x, y) \in C \times D\), \((x, y) \in S\) means that \(\frac{1}{x}-\frac{1}{y}\) is an integer.
a. Is 2 S 2? Is −1S − 1? Is \((3,3) \in S\)? Is \((3,-3) \in S\)?
b. Write S as a set of ordered pairs.
c. Write the domain and co-domain of S.
d. Draw an arrow diagram for S.
Text Transcription:
(x, y) in C times D
(x, y) in S
1/x -1/y
(3,3) in S
(3,-3) in S
Questions & Answers
QUESTION:
Let C = D = {−3,−2,−1, 1, 2, 3} and define a relation S from C to D as follows: For all \((x, y) \in C \times D\), \((x, y) \in S\) means that \(\frac{1}{x}-\frac{1}{y}\) is an integer.
a. Is 2 S 2? Is −1S − 1? Is \((3,3) \in S\)? Is \((3,-3) \in S\)?
b. Write S as a set of ordered pairs.
c. Write the domain and co-domain of S.
d. Draw an arrow diagram for S.
Text Transcription:
(x, y) in C times D
(x, y) in S
1/x -1/y
(3,3) in S
(3,-3) in S
ANSWER:Step 1 of 4
Let and a relation is defined from to as follows:
is an integer.
For ,
As 0 is an integer, therefore, .
Hence, is true.
For ,
As 0 is an integer, therefore, .
Hence, is true.
For ,
As 0 is an integer, therefore, .
For ,
As is not an integer, therefore, .