Use the well-ordering principle to prove that given any integer n 1, there exists an odd
Chapter 5, Problem 24(choose chapter or problem)
Use the well-ordering principle to prove that given any integer n ≥ 1, there exists an odd integer m and a nonnegative integer k such that \(n = 2^{k} \cdot m\).
Text Transcription:
n = 2^k cdot m
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