Solved: a) Show that the current in the kth branch of the circuit in Fig. P3.22(a) is
Chapter 3, Problem 3.22(choose chapter or problem)
a) Show that the current in the kth branch of the circuit in Fig. P3.22(a) is equal to the source current \(i_{g}\) times the conductance of the kth branch divided by the sum of the conductances, that is,
\(i_{k}=\frac{i_{g} G_{k}}{G_{1}+G_{2}+G_{3}+\cdots+G_{k}+\cdots+G_{N}}\)
b) Use the result derived in (a) to calculate the current in the \(5 \ \Omega\) resistor in the circuit in Fig. P3.22(b).
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