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Sketch the 3 d orbitals. How would the 4 d orbitals differ

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 64E Chapter 7

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 64E

Sketch the 3 d orbitals. How would the 4 d orbitals differ from the 3 d orbitals?

Step-by-Step Solution:

Solution Step 1 For naming a binary non metal compound like the one given in the question the general rule is as follows 1) For names start with the element to the left side of the periodic table 2) Add -ide to the second element 3) Use Greek prefixes for number of atoms: mono, di, tetra, penta and so on… Applying this to the compound Cl O 2 7 The name starts with Chlorine and ends in oxide. Adding prefixes -di and-hepta for 1 and 7 the name will be dichlorine heptoxide. Step2 Cl27s formed from the elements Cl and O. The balanced equation will be 2Cl +7O 2Cl O 2(g) 2(g) 2 7(l) Step 3 The boiling point of 81 C is as expected as non metallic oxides usually have a low boiling point. The oxides of non-metals like Sulphur and Chlorine consists of individual molecules. The attractive force between these molecules will be vanderwalls force and thus will be weaker than ionic or covalent bond .Thus the energy required to break these bonds are lesser as evident from the lower boiling points of these molecules. However in Cl O c2o7ne uses all of its seven outer electrons in bonds with oxygen forming a bigger molecule and thus will have boiling point greater than the other non-metallic oxides.

Step 4 of 5

Chapter 7, Problem 64E is Solved
Step 5 of 5

Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

Chemistry: A Molecular Approach was written by and is associated to the ISBN: 9780321809247. Since the solution to 64E from 7 chapter was answered, more than 280 students have viewed the full step-by-step answer. The answer to “Sketch the 3 d orbitals. How would the 4 d orbitals differ from the 3 d orbitals?” is broken down into a number of easy to follow steps, and 17 words. The full step-by-step solution to problem: 64E from chapter: 7 was answered by , our top Chemistry solution expert on 02/22/17, 04:35PM. This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3. This full solution covers the following key subjects: oxidation, state, point, oxygen, boiling. This expansive textbook survival guide covers 82 chapters, and 9464 solutions.

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