Sketch the 3 d orbitals. How would the 4 d orbitals differ

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Problem 64E Chapter 7

Chemistry: A Molecular Approach | 3rd Edition

  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

4 5 0 298 Reviews
17
2
Problem 64E

Sketch the 3 d orbitals. How would the 4 d orbitals differ from the 3 d orbitals?

Step-by-Step Solution:

Solution Step 1 For naming a binary non metal compound like the one given in the question the general rule is as follows 1) For names start with the element to the left side of the periodic table 2) Add -ide to the second element 3) Use Greek prefixes for number of atoms: mono, di, tetra, penta and so on… Applying this to the compound Cl O 2 7 The name starts with Chlorine and ends in oxide. Adding prefixes -di and-hepta for 1 and 7 the name will be dichlorine heptoxide. Step2 Cl27s formed from the elements Cl and O. The balanced equation will be 2Cl +7O 2Cl O 2(g) 2(g) 2 7(l) Step 3 The boiling point of 81 C is as expected as non metallic oxides usually have a low boiling point. The oxides of non-metals like Sulphur and Chlorine consists of individual molecules. The attractive force between these molecules will be vanderwalls force and thus will be weaker than ionic or covalent bond .Thus the energy required to break these bonds are lesser as evident from the lower boiling points of these molecules. However in Cl O c2o7ne uses all of its seven outer electrons in bonds with oxygen forming a bigger molecule and thus will have boiling point greater than the other non-metallic oxides.

Step 4 of 5

Chapter 7, Problem 64E is Solved
Step 5 of 5

Textbook: Chemistry: A Molecular Approach
Edition: 3rd
Author: Nivaldo J. Tro
ISBN: 9780321809247

Chemistry: A Molecular Approach was written by Sieva Kozinsky and is associated to the ISBN: 9780321809247. Since the solution to 64E from 7 chapter was answered, more than 253 students have viewed the full step-by-step answer. The answer to “Sketch the 3 d orbitals. How would the 4 d orbitals differ from the 3 d orbitals?” is broken down into a number of easy to follow steps, and 17 words. The full step-by-step solution to problem: 64E from chapter: 7 was answered by Sieva Kozinsky, our top Chemistry solution expert on 02/22/17, 04:35PM. This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3rd. This full solution covers the following key subjects: oxidation, state, point, oxygen, boiling. This expansive textbook survival guide covers 82 chapters, and 9464 solutions.

×
Log in to StudySoup
Get Full Access to Chemistry: A Molecular Approach - 3rd Edition - Chapter 7 - Problem 64e

Forgot password? Reset password here

Join StudySoup for FREE
Get Full Access to Chemistry: A Molecular Approach - 3rd Edition - Chapter 7 - Problem 64e
Join with Email
Already have an account? Login here
Reset your password

I don't want to reset my password

Need help? Contact support

Need an Account? Is not associated with an account
Sign up
We're here to help

Having trouble accessing your account? Let us help you, contact support at +1(510) 944-1054 or support@studysoup.com

Got it, thanks!
Password Reset Request Sent An email has been sent to the email address associated to your account. Follow the link in the email to reset your password. If you're having trouble finding our email please check your spam folder
Got it, thanks!
Already have an Account? Is already in use
Log in
Incorrect Password The password used to log in with this account is incorrect
Try Again

Forgot password? Reset it here