×
Log in to StudySoup
Get Full Access to Chemistry - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Chemistry - Textbook Survival Guide

An electron in a hydrogen atom relaxes to the n = 4 level,

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 72E Chapter 7

Chemistry: A Molecular Approach | 3rd Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

4 5 1 264 Reviews
30
5
Problem 72E

An electron in a hydrogen atom relaxes to the n = 4 level, emitting light of 114 THz. What is the value of n for the level in which the electron originated?

Step-by-Step Solution:
Step 2 of 4

Solution (a)The balanced equation for the reaction between potassium and hydrogen is as given below 2K (s) 22 (g) (s) (b)Let us find the energy changes for the 2 reactions separately in order to compare them. The first reaction + - K (g) K (g) (g)H (g) can be split into the following 2 steps K K + +e -------eqn 1 ,energy required E =I.E=+419 KJ/mole (g) (g) 1 H (g)H -(g) -------eqn 2 ,enegy required E =E.A=-73KJ/2le Thus the net energy change required for the process will be sum of the energy changes for both reactions(E +E ) 1 2 =Ionisation energy of K+Electron gain enthalpy of H =+419 KJ/mole -73KJ/mole) =346 KJ/mole The second reaction is as given below K +H K - +H + (g) (g) (g) (g) Splitting it into 2 steps + - H (g) (g)e -------eqn 1,energy required E =I.E=+1312 KJ3ole - - K (g)K (g) --------eqn 2 ,enrgy required E =E.A=-48KJ4ole Thus the net energy change required for the process will be sum of the energy changes for both reactions(E +E ) 3 4 =Ionisation energy of H+Electron gain enthalpy of K =+1312 KJ/mole -48KJ/mole =1264KJ/mole

Step 3 of 4

Chapter 7, Problem 72E is Solved
Step 4 of 4

Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

The full step-by-step solution to problem: 72E from chapter: 7 was answered by , our top Chemistry solution expert on 02/22/17, 04:35PM. Since the solution to 72E from 7 chapter was answered, more than 344 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Chemistry: A Molecular Approach, edition: 3. This full solution covers the following key subjects: elements, potassium, figure, Energy, mol. This expansive textbook survival guide covers 82 chapters, and 9454 solutions. Chemistry: A Molecular Approach was written by and is associated to the ISBN: 9780321809247. The answer to “An electron in a hydrogen atom relaxes to the n = 4 level, emitting light of 114 THz. What is the value of n for the level in which the electron originated?” is broken down into a number of easy to follow steps, and 32 words.

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

An electron in a hydrogen atom relaxes to the n = 4 level,

×
Log in to StudySoup
Get Full Access to Chemistry - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Chemistry - Textbook Survival Guide
×
Reset your password